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Position of a particle is given by x = (2 cm) cos 10πt

  1. Nov 17, 2011 #1
    1. The problem statement, all variables and given/known data

    The position of a particle is given by x = (2 cm) cos 10πt, where t is in seconds.
    (a) What is the frequency?
    (b) What is the period?
    (c) What is the amplitude of the particle's motion?
    (d) What is the first time after t = 0 that the particle is at its equilibrium position?
    sIn what direction is it moving at that time?
    in the negative direction
    in the positive direction

    2. Relevant equations

    3. The attempt at a solution
  2. jcsd
  3. Nov 18, 2011 #2
    Re: Harmonics

    The general form of the equation you are using is
    x = ACos(ωt)
    x is the displacement, A is the amplitude and ω is the ANGULAR frequency
    Hope this helps
  4. Nov 18, 2011 #3
    Re: Harmonics

    You will need to show some working first, where are you having problems and what have you done so far?
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