1. The problem statement, all variables and given/known data A force of 10 Newtons can stretch a spring by 0.04 m. Suppose a mass of 5 kg is attached to the lower end of the spring. We stretch the mass downward by 0.05 m from its equilibrium position and release it from rest. Determine the position of the mass relative to its equilibrium position at t = 0.5 seconds. Assume no damping. 2. Relevant equations k = F/x w= k/m x(t) = A cos wt + B sin wt 3. The attempt at a solution k = 10/ 0.04 = 250 N/m x(0) = -0.05 x`(0) = 0 w= (250/5)^1/2 = 50^1/2 equation x(t) = -0.05cos( (50^1/2) t)) substituting t= 0.5, -0.049904837 but the answer is -0.04617 I do not know where I messed up.