Possible Fourth Corners of a Parallelogram Given Three Non-Collinear Points

  • Thread starter Thread starter zeion
  • Start date Start date
  • Tags Tags
    Parallelogram
Click For Summary
SUMMARY

The discussion centers on determining the possible fourth corners of a parallelogram given three non-collinear points: (1,1), (4,2), and (1,3). The confirmed fourth corner is (4,4), while additional valid corners include (4,0) and (-2,2). This conclusion is derived from the geometric properties of parallelograms, specifically that any triangle can define three distinct parallelograms by rotating the triangle around its vertices.

PREREQUISITES
  • Understanding of coordinate geometry
  • Familiarity with the properties of parallelograms
  • Knowledge of triangle geometry
  • Ability to graph points and visualize geometric shapes
NEXT STEPS
  • Explore the properties of parallelograms in depth
  • Learn about triangle transformations and their implications in geometry
  • Study coordinate geometry techniques for finding unknown points
  • Investigate the concept of symmetry in geometric shapes
USEFUL FOR

Students studying geometry, educators teaching coordinate geometry, and anyone interested in the properties of shapes and their transformations.

zeion
Messages
455
Reaction score
1

Homework Statement



If three corners of a parallelogram are (1,1), (4,2), and (1,3), what are all the possible fourth corners?


Homework Equations





The Attempt at a Solution



The only possible fourth corner is (4,4) if the other 3 points are set.
The solution says (4,0) and (-2,2) can also be corners. How is this possible
 
Physics news on Phys.org
Take the problem description to a graph of the points given, and literally test the answer key solution visually; is it also a vertex of a parallelogram? Now, if so, how can you account for this symbolically?
 
Note that given 3 non-collinear points A, B, & C, you can create a triangle [itex]\triangle[/tex]ABC<br /> <br /> A parallelogram, when divided along one of its diagonals, results in two identical triangles rotated 180[itex]^\circ[/tex] with respect to each other.<br /> So, any triangle can describe 3 parallelograms.[/itex][/itex]
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 20 ·
Replies
20
Views
3K
Replies
7
Views
4K
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
10
Views
18K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 2 ·
Replies
2
Views
5K