MHB Possible title: How to Find the Derivative of y=e-.5x?

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To find the derivative of the function y=e^(-0.5x), apply the chain rule, which states that the derivative of e^(f(x)) is e^(f(x)) multiplied by the derivative of f(x). The derivative of -0.5x is -0.5, leading to the final result of dy/dx = -0.5e^(-0.5x). The assertion that the answer is zero is incorrect; the derivative is a non-zero value. Understanding the chain rule and the properties of the exponential function is crucial for solving such problems. Mastering these concepts will improve proficiency in calculus.
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what are the steps in finding the derivative of the function y=e-.5x

and why is the answer zero?

sorry I'm posting like 150 threads, I'm just really bad at math.
 
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coolbeans33 said:
what are the steps in finding the derivative of the function y=e-.5x

and why is the answer zero?

sorry I'm posting like 150 threads, I'm just really bad at math.

$$\frac{dy}{dx} \ne 0$$. What have you tried? In general, what is $\dfrac {d}{dx} e^{x}$? What about $\dfrac{d}{dx} e^{f(x)}$?

Also, 2k posts! :D
 
coolbeans33 said:
what are the steps in finding the derivative of the function y=e-.5x

and why is the answer zero?

sorry I'm posting like 150 threads, I'm just really bad at math.

Uh? :confused:
The answer is not zero.

The steps are the application of the chain rule.
Combined with the rule that the derivative of $e^x$ is $e^x$.

Didn't you just apply the chain rule in your previous thread?
Rather successfully in a more complicated problem I might add?
 
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Hello! I tried to calculate projections of curl using rotation of coordinate system but I encountered with following problem. Given: ##rot_xA=\frac{\partial A_z}{\partial y}-\frac{\partial A_y}{\partial z}=0## ##rot_yA=\frac{\partial A_x}{\partial z}-\frac{\partial A_z}{\partial x}=1## ##rot_zA=\frac{\partial A_y}{\partial x}-\frac{\partial A_x}{\partial y}=0## I rotated ##yz##-plane of this coordinate system by an angle ##45## degrees about ##x##-axis and used rotation matrix to...
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