1. The problem statement, all variables and given/known data A horizontal spring with psring constant k = 15.19 N/m is compressed 23.11 cm fro mits equil. position. A hockey puck with mass m = 170.0g is placed against the end of the spring. The friction coefficient is 0.02221. How far does the hockey puck travel? k = 15.19 N/m x = 0.2311 uk = 0.02221 m = 0.17 2. Relevant equations 1/2mv^2 = 1/2kx^2 = friction force potential 3. The attempt at a solution x = (kx^2)/ ( 2*0.02221*mg) = 10.9m x should be equal to 23.11 cm... I really don't understand why I keep getting a huge number when it shold actually be 23.11 cm. Also, I do understand tat 1/2mv^2 = 1/2kx^2 but why is any of those = to frictional force potential? Thank you!