- #1

hamishmidd

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- Homework Statement
- A mass m is hung from a spring with spring constant k. The mass is kicked upwards such

that it has a speed of v when the mass is at the equilibrium position. What is the maximal displacement of the mass from the equilibrium position as the mass subsequently

oscillates?

- Relevant Equations
- Ek=1/2mv^2, U=1/2kx^2, kx=mg (at equilibrium position)

I have tried to answer this using the relevant equations I am provided on my formula sheet, however I get stuck pretty close to the end. I start with 1/2mv^2=1/2kx^2 at the equilibrium position, and kx=mg, x=mg/k. This gets me to v^2=mg^2/k, but I don't know where to go from there. The potential answers are:

(A) x = v*sqrt(m/k) (B) x =v^2/2g (C) x =sqrt(2mv/k) (D) x = vt +1/2gt^2 (E) None of the above

(A) x = v*sqrt(m/k) (B) x =v^2/2g (C) x =sqrt(2mv/k) (D) x = vt +1/2gt^2 (E) None of the above