Potential Energy: Hiker at 1600m to 3100m - Change, Work, & Explanation

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Homework Help Overview

The discussion revolves around a physics problem involving potential energy and work related to a hiker ascending from an elevation of 1600 m to 3100 m. The problem prompts participants to explore the change in potential energy, the minimum work required, and the possibility of actual work exceeding this minimum.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of potential energy change using the formula mgh and question the implications of actual work done compared to minimum work. There is also a mention of aerodynamic drag as a factor influencing the work done.

Discussion Status

The discussion is active, with some participants expressing confidence in their understanding of potential energy calculations while others are seeking clarification on related concepts, such as the impact of aerodynamic drag on work done.

Contextual Notes

Some participants indicate familiarity with certain parts of the problem but express uncertainty about others, particularly regarding the implications of external forces like drag. The original poster's inquiry includes multiple parts, which may lead to varied interpretations and approaches.

rphmy
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A 55-kg hiker starts at an elvation of 1600 m and climbs to the top of a 3100-m peak. (a) What is the hiker's change in potential energy? (b) What is the minimum work required of the hiker? (c) Can the actual work done be more than this? Explain
 
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i know how to do part a, but can you by any chance help me with my problem, its titeled LOOP problem with DIAGRAM!
 
a) mgh= mgh
55(9.81)(1600)=(55)(9.81)(h)

you just solve for height by the equation above.
 
> Can the actual work done be more than this?

What's the aerodynamic drag at 1 to 3 miles per hour?
 

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