Ok so my problem was: A 80 kg hiker starts at an elevation of 1600 m and climbs to the top of a 3600 m peak.(adsbygoogle = window.adsbygoogle || []).push({});

(a) What is the hiker's change in potential energy?

J

(b) What is the minimum work required of the hiker?

J

(c) Can the actual work done be more than this? YES!!

so i figured out a) Change in PE = mg(y2-y1)

=80kg(9.8 m/s^2)(3600m-1600m)

= 1.56 x 10^6 Joules

B) Part b is the same answer cause with your PE you can perform minimum work

But for C i dont understand how the actual work be more than delta PE?

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# Homework Help: Work and enegry theoretical problem

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