Potential Energy of 2 Masses Connected by a String - Find Theta

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Homework Help Overview

The discussion revolves around a problem involving two masses connected by a string, focusing on determining the equilibrium point in terms of the angle theta. The context is centered on potential energy and its relationship to the angle in a geometric setup.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss how to express potential energy as a function of theta and explore the geometric relationships between the masses and the angle. There is an attempt to derive the vertical distances of the masses from a reference point.

Discussion Status

Some participants have provided guidance on finding the distances of the masses in relation to the angle, while others express uncertainty about how these relationships contribute to the overall problem. The discussion reflects a mix of attempts and clarifications without a clear consensus on the next steps.

Contextual Notes

One participant notes that the problem is part of extra practice rather than a formal homework assignment, which may influence the approach taken in the discussion.

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Homework Statement



A figure is attached.
A string with length L connects two beads with masses M1,M2.
what is the equilibrium point?(in terms of the angle theta,as in the figure)

The Attempt at a Solution



well I know that I need to find the potential energy as a function of theta,and then find the minimum.

but I don't know how to express the potential energy in terms of theta
 

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You know the distance between m1 and m2 is L. To get started, find the distances of m1 and m2 from the rightangle in terms of L and theta.
 
well this is easy

for m1 : l*cos(theta)
for m2 : l*sin(theta)

I can't see how this is helping me
(by the way,this is not homework,I'm doing extra problems from the book)
 
The potential energy of a mass = mgh where h is the vertical distance from some point.

From those lengths, finding the vertical distance of the masses below the right angle (using alpha) is also easy.
 
can't believe I didnt see it..really easy

thanks :)
 

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