Potential Energy/ The Isolated system

In summary, the problem involves a ball of mass 8 kg being dropped from a height of 13.9m with an initial downward speed of 4.9 m/s. The question asks for the final speed of the ball when it reaches a height of 0.7m, ignoring air resistance. The relevant equation is Kf+Ugf=Ki+Ugi which is 1/2mvf2+mgy=1/2mvi2 +mgh. The final speed can be calculated by finding the kinetic energy of the ball after it has fallen 0.7m.
  • #1
aaronb
23
0

Homework Statement



A ball of mass m = 8 kg is dropped from rest at a height h = 13.9 m above the ground, as in Figure 7.4. Ignore air resistance.

If the ball is being released with a downward speed 4.9 m/s initially, what will be its final speed when it hits the table 0.7 m below the release point?

Homework Equations



Kf+Ugf=Ki+Ugi which is 1/2mvf2+mgy=1/2mvi2 +mgh

The Attempt at a Solution


I am confused in the wording of the question. What do they mean by "final speed when it hits the table 0.7m below the release point?"
 
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  • #2
aaronb said:

Homework Statement



A ball of mass m = 8 kg is dropped from rest at a height h = 13.9 m above the ground, as in Figure 7.4. Ignore air resistance.

If the ball is being released with a downward speed 4.9 m/s initially, what will be its final speed when it hits the table 0.7 m below the release point?

Homework Equations



Kf+Ugf=Ki+Ugi which is 1/2mvf2+mgy=1/2mvi2 +mgh

The Attempt at a Solution


I am confused in the wording of the question. What do they mean by "final speed when it hits the table 0.7m below the release point?"

They mean the full speed it was going right when it hits the table. Of course the table stopping it will quickly accelerate it down to a velocity of 0, but we want to know the velocity before the table actually stops it.

The important information is .7m. How much kinetic energy will it have when it's fallen .7 meters from where it was dropped?
 
  • #3
So it's just asking for the speed of the ball after it has fallen 0.7m?
 
  • #4
aaronb said:
So it's just asking for the speed of the ball after it has fallen 0.7m?

Apparently so.

I will presume that the first question was the speed or kinetic energy when it hit 13.9m below?
 
  • #5
Nope. The first question asked for the speed at an arbitrary height before the ball hit the ground. In that case it was 5.2m
 

1. What is potential energy?

Potential energy is the energy that an object possesses due to its position or configuration. It is stored energy that has the potential to do work.

2. How is potential energy related to the isolated system?

In an isolated system, energy cannot be transferred to or from the surrounding environment. Therefore, potential energy within the system remains constant and is not affected by external factors.

3. What are some examples of potential energy in an isolated system?

Some examples of potential energy in an isolated system include gravitational potential energy, elastic potential energy, and chemical potential energy. For instance, a stretched spring, a raised object, or a chemical bond can all possess potential energy in an isolated system.

4. How is potential energy converted into other forms of energy in an isolated system?

In an isolated system, potential energy can be converted into other forms of energy, such as kinetic energy, thermal energy, or electrical energy. This conversion occurs when work is done on the object, or when an external force acts on the object, causing it to move or change in position.

5. Can potential energy be negative in an isolated system?

Yes, potential energy can be negative in an isolated system. This can occur when the reference point for measuring potential energy is chosen arbitrarily. For example, if the reference point is set at a lower height, then an object at a higher height would have negative gravitational potential energy.

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