Why is the final potential of spring (Usf) equal to zero in problem b?

In summary, the conversation discusses a problem with b and the given equation. The person checked the solution but did not understand the logic behind it. They specifically question why the final potential of the spring (Usf) is equal to zero. After reading the problem in detail, it is explained that the potential energy stored in a spring depends on how far it is being compressed or stretched. Since the object in b is at the bottom of the incline and no longer in contact with the spring, it is not compressing it and therefore has no stored energy. The person thanks the expert for their summary and understanding after posting their question.
  • #1
F1ght4h0n0uR
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I'm having promblem with b. I checked the solution, but I did'nt understand the logic.

Kf+Ugf+Usf = Ki+Ugi+Usi

Usf= 0, Ki=0, Ugf= 0

I understand the logic's why they are equal to 0.

I don't understand why final potential of spring (Usf) is equal to zero?

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Now, I got it. I read the problem in detail.
 
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  • #2
The potential energy that is stored in a spring depends on how far something is compressing or stretching the spring. So in b, when the object is at the bottom of the incline, it is no longer in contact with the spring, meaning it cannot be compressing the spring. since it is not compressing the spring that means there is no energy stored in it.
 
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  • #3
Joseph Martinez said:
The potential energy that is stored in a spring depends on how far something is compressing or stretching the spring. So in b, when the object is at the bottom of the incline, it is no longer in contact with the spring, meaning it cannot be compressing the spring. since it is not compressing the spring that means there is no energy stored in it.

Thank you so much, I see it after posting thread.
 

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