Potential + Kinetic Energy Question

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SUMMARY

The discussion centers on a physics problem involving a 15.0 kg model plane flying at 12.5 m/s. The kinetic energy calculated for the plane is 1172 J. During a power dive, the plane descends 20.4 m, resulting in a loss of potential energy calculated at 2998 J, which is converted into kinetic energy. The total kinetic energy after the dive is determined to be 4170 J, confirming the conservation of energy principle where energy is neither created nor destroyed.

PREREQUISITES
  • Understanding of kinetic energy calculations using the formula KE = 0.5 * m * v^2
  • Knowledge of potential energy calculations using the formula PE = m * g * h
  • Familiarity with the law of conservation of energy
  • Basic grasp of physics concepts related to motion and energy transfer
NEXT STEPS
  • Study the principles of energy conservation in mechanical systems
  • Learn about the effects of air resistance on energy calculations in real-world scenarios
  • Explore advanced kinetic and potential energy problems in physics textbooks
  • Practice solving similar physics problems involving energy transformations
USEFUL FOR

Students studying physics, educators teaching energy concepts, and anyone interested in understanding the dynamics of energy conservation in motion.

NDiggity
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Homework Statement


A 15.0 kg. model plane flies horizontally at 12.5m/s. Part a) asks for kinetic energy. I got 1172J. Part b) says the plane goes into a power dive and levels off 20.4 m closer to the earth. How much energy did it lose during the dive. I got 2998.8J. Doesn't really make sense.

Then part c) asks how much kinetic energy did the plane gain during the dive. I'm lost. Please help.
 
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the first question is right.

the second one, "how much do it loose"
well since it is falling, it must loose some potential energy. But energy can not be destroyed; so it does not loose any total energy.

Think of this:
When you let a rock fall free from a buildning, an ignore air resistance, what is happening with the rock from an energy point of view?
 
It is transfering potential to kinetic. So for part b) it loses no energy. For part c) i found out the potential energy it would lose to be 2998 J. So the kinetic energy gained 2998 J. Part D asks what the new kinetic energy would be, so I added 1172 and 2998. Is this better? PS, thank you for your help. I appreciate how no matter how basic some of the question I ask are, no one is sarcastic or demeaning.
 
Last edited:
for part (b) i guess the question should have been, how much potential energy the plane has lost? then you use the equation to find the potential energy converted to kinetic energy.

using the law of conservation of energy, potential energfy lost = kinetiv energy gained.

i think you're right for part (d)
 
Energy is conserved, so NDiggity is correct. No energy is lost, the plane travels faster in the lower orbit. The drop in potential energy is offset by the gain in kinetic energy [disregarding friction].
 

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