Power Dissipated by 60W Bulb in 20V Source[/B]

AI Thread Summary
The discussion focuses on calculating the power dissipated by a 60W light bulb when connected to a 20V source, given that the bulb's resistance remains constant. Initially, the participants derive the bulb's resistance from its rated power and voltage, determining it to be 240 ohms. They then apply the formula P = V²/R to find the power at the lower voltage, resulting in approximately 1.67 watts. An alternative method is also discussed, which involves using the ratio of the voltages to simplify the calculation. Ultimately, the correct power dissipation is confirmed to be around 1.67 watts.
estike
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Homework Statement



What is the power dissipated by a 60 Watt (rated at 120 V) light bulb if it is connected to a 20 V power source (assume the resistance of the bulb is constant)?

Homework Equations

The Attempt at a Solution



If it [/B]
 
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Hello E, welcome to PF :smile: !

You were saying ?
 
I don't know where to start i know that the power dissipated is in Joules but i don't know what equation to use
 
Power is actually measured in Watts.

You initially have a 60W bulb running on 120V. What equation relates Power, Voltage and Current?
 
Ohm´s law V=RI
 
W = VC right ?
 
Yes Ok but better to write it as P = I * V.

Now using that and Ohms law write a new equation relating Power, Voltage and Resistance.
 
if 60 = 120 * I = 0.5 A

I use this current and know that is 120V*0.5A = W right ? and W is 60 right
 
Yes Ok the current is 0.5A.

You actually need to calculate the resistance as well.
 
  • #10
hum ok i understand know so if V= RI since 220 = R *0,5A = so the resistence is 110 ohms and since is constant

20 = 110*i = so I =0.182 A

So P = I*V = 0.182 A*20 = 3.6 Watts ? Am i right ?
 
  • #11
hum ok i understand know so if V= RI since 220= R *0,5A

should be 120V.
 
  • #12
so is 120 = R * 0.5A = 60 ohms

And then 20 = 60*I = 1/3 A

so W = 1/3A*20 V = 6,66 watts right
 
  • #13
Back later.
 
  • #14
but the answers are 60W , 1.67 W , 20W or 120W i really don't understand then :x
 
  • #15
i know what i did wrong it was 240 ohms i made a stupid error

W = 1/12A*20V and then it is 1,67 W
 
  • #16
Sorry I got called away..

Ok you got to the right answer but there is an easier route that I was trying to lead you down in post #7. I think you're substituting values too soon. There is no need to work out the current in either circuit. Here is how I would do it...

P = I * V
V = I * R

Substitute to eliminate I..

P = V2/R (Aside: I memorised that one and also P = I2 * R)

Rearrange to give R...

R = V2/P

Substitute values..

= 14400/60
= 240 Ohms

For second circuit R is the same. V changes to 20V...

P = V2/R
= 202/240
= 1.7W
 
  • #17
You can also do it without working out R...

P1 = V12/R
P2 = V22/R

P2 / P1 = V22 / V12

P2 = P1 * V22 / V12

= 60 * 202/1202
= 1.7W
 
  • #18
@estike you are right, the value is 5/3 = 1.666...
 
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