Power & Kinetic Energy Needed to Pull Wagon at 25km/hr

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SUMMARY

The discussion focuses on calculating the power required to pull a wagon weighing 32,200 N at a speed of 25 km/h, given a coefficient of rolling resistance of 0.200. The key equations involved include the frictional force formula, Ff = U * normal force, where U is the coefficient of rolling resistance. The normal force is equal to the weight of the wagon when it is on a flat surface. The power can then be calculated using the relationship between force and velocity.

PREREQUISITES
  • Understanding of basic physics concepts, specifically forces and motion.
  • Familiarity with the formula for frictional force, Ff = U * normal force.
  • Knowledge of how to calculate power using the formula Power = Force x Velocity.
  • Basic understanding of kinetic energy calculations.
NEXT STEPS
  • Study the relationship between force, velocity, and power in physics.
  • Learn how to calculate normal force in various scenarios.
  • Explore kinetic energy formulas and their applications.
  • Review examples of problems involving rolling resistance and power calculations.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of power and kinetic energy in mechanical systems.

joepro
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Hello, I am having a hard time figuring out some physics problems.

The problem states.

How much power is required to pull a wagon weighingi 32200N at the speed of 25.0km/hr f the coefficient of rolling resistance is 0.200? What is the kinetic energy of the wagon?
______KW
______J

Thanks for the help!
 
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What equations do you think you will need to solve this problem?
 
I knowI need Ff=UN but otherwise I do not understand how to put the acceleration problem together with the friction problem or where to even start.
 
joepro said:
I knowI need Ff=UN but otherwise I do not understand how to put the acceleration problem together with the friction problem or where to even start.

You don't need acceleration for this problem. You can get Ff using the formula. So now how does Power relate to force and velocity?
 
My U is .200 and I know that Ff=U * normal force. How do I find the normal force, then one I find the normal force what do I do to find the required power. I just need some steps and guidence. Thanks
 
joepro said:
My U is .200 and I know that Ff=U * normal force. How do I find the normal force, then one I find the normal force what do I do to find the required power. I just need some steps and guidence. Thanks

The normal force or the normal reaction is an upward force acting on the car. The only other force acting in the vertical direction is the weight which acts downwards. So if the car does not move up or down, then what is the normal force equal to?
 

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