Power of a car, time distance speed mass

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SUMMARY

The discussion centers on calculating the power of a car with a mass of 1 metric ton (1000 kg) that accelerates to a speed of 20 m/s in 5 seconds. The book states the power is 40 kW, while the user calculates it as 80 kW. The correct approach involves using the formula P = Fv, where F is the force calculated as F = ma, resulting in 80 kW. The confusion arises from the distinction between final speed and average speed, emphasizing the need to consider average power over time.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of power calculations (P = Fv and P = A/t)
  • Familiarity with kinematic equations for motion
  • Basic concepts of energy and work (A = Fs)
NEXT STEPS
  • Study the concept of average power versus instantaneous power in physics
  • Learn about kinematic equations and their applications in motion analysis
  • Explore the relationship between force, mass, and acceleration in practical scenarios
  • Investigate energy conservation principles in mechanical systems
USEFUL FOR

Students in physics, automotive engineers, and anyone interested in understanding the dynamics of vehicle power and acceleration calculations.

abruski
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Homework Statement



A car with mass m = 1 metric ton (1000 kg) in time t = 5 seconds reaches speed v = 20 m/s

What is the power of the car? P = ? kW (kilo Watts)

Homework Equations



F - force, a - acceleration, A - work, s - distance

P = \frac{A}{t}

P = Fv

F = ma

a = \frac{v}{t}

A = Fs

s = vt

The Attempt at a Solution



The answer given in the book is 40 kW but I get 80 kW. With the 40 kW I get that the acceleration s 2 m/s^{2}, which means that
\frac{v}{t} = \frac{20}{5} = 2

??

Maybe I miss something. Any help is appreciated.
 
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abruski said:
The answer given in the book is 40 kW but I get 80 kW.
Show how you got your answer. Hint: Find the average power.
 
a = \frac{v}{t} = \frac{20}{5} = 4 \frac{m}{s^{2}}

s = vt = 100 m

F = ma = 1000*4 = 4000 N

A = Fs = 4000*100 = 400000 J


P = Fv = 4000*20 = 80 000 W

P = \frac{A}{t} = \frac{400000}{5} = 80 000 W

seems pretty straightforward to me
 
40 kW is a correct answer.

Distance is not 100 m.

While the final answer should be identical no matter how you solve the question, comparing final energy of the car with the work done seems to be much easier approach.
 
how come distance is not 100m?
 
20 m/s is a FINAL speed, not average.
 
What about the acceleration?
 
abruski said:
What about the acceleration?
What about it? Realize that the instantaneous power varies throughout the motion. You want the average power. Rather than mess around with kinematics, use the most basic definition of power as energy/time.
 

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