# Power up and incline with friction

1. Sep 29, 2008

### Kajayacht

1. The problem statement, all variables and given/known data
A 1400 kg block of granite is pulled up an incline that has an angle of inclination θ = 29 ° with a constant speed of 1.13 m/s by a steam winch (see Figure). The coefficient of kinetic friction between the block and the incline is 0.12. How much power must be supplied by the winch?

2. Relevant equations
T= uW/cos(theta)+u*sin(theta)
P=Fv

3. The attempt at a solution
T= .12(1400*9.8)/cos(29)+.12*sin(29)
T= 1765.0 N

P= FV
P= 1765*1.13
P= 1994.5 W

2. Sep 29, 2008

### LowlyPion

That equation does not look correct

3. Sep 29, 2008

### Kajayacht

wait do you mean the equation itself or I put in the values wrong?

4. Sep 29, 2008

### LowlyPion

That equation is incorrect.

5. Sep 29, 2008

### Kajayacht

Figured that much, but I was hopeful.

Could you give me a hint or something, I think I might now the equations I need but my notebook is at my dorm right now and my next class is about to start.

6. Sep 29, 2008

### LowlyPion

Tension is going to equal the frictional resistance and the weight down the incline.