Power wasted in a cell with internal resistance

[ad_astra]

a cell of emf 1.5V and internal resistance 0.5 ohms is connected to a 2.5 ohm resistor.

ive calculated the current as 0.5A
terminal pd as 1.25V
and calculated the power delivered to the 2.5 ohm resistor.

now i have to calculate the power wasted in the cell?

ive got the equation Ie = I^2 + I^2r
which is the power supplied by the cell = the power delivered to R + the power wasted in the cell.

but I am so confused. on rearranging it and subsituting the numbers in?

can anyone shed any light on how i do this? and if so can you give me the equation and talk me through it please..

thanks :)

 

[vk6kro]

Hint:
How much power is dissipated in the internal resistance of the battery?

A battery can only generate power but a resistor can "waste" it.

 

[ad_astra]

ahh.. so i jus find out the amount of power delivered to the internal resistor and then that's my wasted power?

 

[vk6kro]

Yes, that's right.

Asking it like that just turned a simple problem into a difficult one.