Preparing 40mM TES pH 7.4 - Calculating A-/HA

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Discussion Overview

The discussion revolves around the preparation of a 40mM TES buffer at pH 7.4, focusing on the calculations related to the concentrations of the acid and its conjugate base. Participants explore the necessary molar masses and the stoichiometry involved in achieving the desired pH.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant expresses uncertainty about the molar mass of the acid and base, questioning whether the given molar mass refers to the acid and how to calculate the base's molar mass.
  • Another participant confirms that the given molar mass refers to the acid and suggests that the base's molar mass can be derived by subtracting the weight of a proton from the acid's molar mass.
  • A different participant proposes that it is unnecessary to know the molar mass of the conjugate base and suggests using enough acid to prepare the solution and neutralizing it with a strong base.
  • One participant calculates the amount of TES needed and the moles of strong base required to convert a portion of the acid to base, providing a specific calculation for the mass of TES to be added.
  • Another participant challenges the calculations, indicating that if more than half of the acid is converted to base, the pH would exceed the pKa, suggesting a need for careful consideration of the ratios used.
  • A later reply corrects the previous percentage of acid converted to base, stating it should be 44% instead of 56%.

Areas of Agreement / Disagreement

Participants express differing views on the necessity of knowing the molar mass of the conjugate base and the implications of the acid-base ratio on the pH. The discussion contains multiple competing views and remains unresolved regarding the best approach to the calculations.

Contextual Notes

Participants rely on specific assumptions about the relationships between the acid and base, as well as the calculations involved in preparing the buffer solution. There are unresolved mathematical steps and dependencies on definitions of the components involved.

vande060
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Homework Statement



prepare 40mM TES buffer pH 7.4
prepare 100mls of it
mw TES = 229.25
pka = 7.5



Homework Equations



ph = pka +log(A-/HA)



The Attempt at a Solution



My problem is that I don't know what the MW of the acid or base is for this buffer. Is the given MW the acid, and I subract a proton weight for the base or something? I can do the calculation though:



7.4 = 7.5 +log(A-/HA)

-.1 = log(A-/HA)

A-/HA = .79

56% base
44% acid

.56* 40mM * MW of base *.1L = moles of base
.44*40mM *MW of acid *.1L = moles of acid

So how should I figure out the MW of acid and base?
 
Physics news on Phys.org
http://en.wikipedia.org/wiki/TES_(buffer )

Given molar mass refers to the acid.
 
Last edited by a moderator:
Borek said:
http://en.wikipedia.org/wiki/TES_(buffer )

Given molar mass refers to the acid.

Thank you,

Ok, that's kind of what I thought. So the acid MW is 229.25, and the base would be (229.25 - 1.008) is that correct?
 
Last edited by a moderator:
You don't need molar mass of the conjugate base. Use enough acid to prepare 40 mM solution, neutralize it with any strong base.
 
so I would go:


229.25g/mol * .04moles/liter *.1L = .917g TES added

then to calulate strong base needed to convert 56% of acid to base

.04moles/liter *.1L = .004 moles TES * .56 = .00224 moles of strong base needed
 
Check your math. If more than half of the acid is converted to base pH is higher than pKa.

But in general you are on the right track.
 
Borek said:
Check your math. If more than half of the acid is converted to base pH is higher than pKa.

But in general you are on the right track.

whoops it should be 44% converted to base
 

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