Pressure 150m Below Sea Surface: Calculate Now!

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Homework Help Overview

The discussion revolves around calculating the pressure at a depth of 150 meters below the sea surface, using the density of seawater provided as 1.026 g/cm³. Participants are exploring the relationship between depth, density, and pressure in a fluid context.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive the pressure using the formula P = pdg, incorporating unit conversions and calculations. Some participants question the validity of the textbook's pressure value compared to their calculations.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the calculations and questioning the accuracy of the textbook reference. There is no explicit consensus on the correctness of the original poster's calculations or the textbook's values.

Contextual Notes

Participants are discussing unit conversions and the meaning of dynes, indicating some uncertainty about the units involved in pressure calculations.

sodr2
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Homework Statement


Calculate thy pressure 150m below the surface of za sea. The density of sea water is 1.026 g/cm3.


2. Homework Equations & The attempt at a solution
The pressure will depend on how much water is above you...

F = mg
F = pVg --- since density = mass per volume
F = pAdg --- since volume = area * depth
F/A = pdg
Therefore Pressure = pdg

------conversion of units--------
9.8 m/s2 * 100 cm/1 m = 980 cm/s2
150 m = 15 000 cm
--------------------------------

P = (1.026 g/cm3) * 150 000 cm * (980 cm/s2)
P = 150 822 000 g/cm2

But my textbook says 1.51 x 107 dyn/cm2 (= 15 atm)

So is my textbook wrong, or what did I do :redface: ?
 
Physics news on Phys.org
Btw, what is dyn?
 
:frown:

Thanks.
 

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