Pressure drop over double parallel system

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SUMMARY

The pressure drop calculation for a double parallel system with 8 heat exchangers and 3 manifolds totals 6.71 KPa. Each heat exchanger has a resistance of 1.333 KPa, while each manifold contributes 1.85 KPa, and the main distribution tubes add approximately 3.53 KPa. The system operates with a flow rate of 24 L/min at 60 degrees Celsius. It is crucial to select an appropriate pump based on this total pressure drop to ensure optimal performance.

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Anansi
I have a system where pipes run 24l L/min of water @60 degrees through 3 manifolds and those manifolds distribute the water over 8 heat exchangers. Every heat exchanger requires 1 L/min, and has a resistance of about 1.333 KPa per heat exchanger at that flow (2 meter @ 9mm diameter + 2 connectors with CV=0.85). Every manifold has a resistance of 1.85 KPa (2 connectors with CV=5.77, resistance of tube is negligible here). The main distribution tubes are 4 meters long at 20mm and carry the full load of 24 L/min that should add up to about 3.53 KPa.

As far as I can tell I need to only count the resistance of all these parts once because they are parallel so the total pressure drop over the system is 1.333+1.85+3.53=6.71 KPa. But its rather important to select the right pump for the system so would really like a verification for this.
 
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Anansi said:
As far as I can tell I need to only count the resistance of all these parts once because they are parallel...
Your analysis looks good to me (without commenting on the numeric values).
 

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