MHB Prime Elements in Non-Integral Domains?

Math Amateur
Gold Member
MHB
Messages
3,920
Reaction score
48
On page 284 Dummit and Foote in their book Abstract Algebra define a prime element in an integral domain ... as follows:View attachment 5660My question is as follows:

What is the definition of a prime element in a ring that is not an integral domain ... does D&F's definition imply that prime elements cannot exist in a ring that is not an integral domain ... but why not ...?Can someone please clarify this situation ...

Peter
 
Physics news on Phys.org
The definition is aiming at the following theorem:

For a commutative ring $R$ and an ideal $J$:

$J$ is prime $\iff \ R/J$ is an integral domain.

The definition of prime element is the same for a mere commutative ring, but commutative rings with zero-divisors aren't so well-behaved, and primes aren't as "useful" there.
 
Thread 'How to define a vector field?'
Hello! In one book I saw that function ##V## of 3 variables ##V_x, V_y, V_z## (vector field in 3D) can be decomposed in a Taylor series without higher-order terms (partial derivative of second power and higher) at point ##(0,0,0)## such way: I think so: higher-order terms can be neglected because partial derivative of second power and higher are equal to 0. Is this true? And how to define vector field correctly for this case? (In the book I found nothing and my attempt was wrong...

Similar threads

Replies
20
Views
5K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 5 ·
Replies
5
Views
796
  • · Replies 84 ·
3
Replies
84
Views
10K
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
734