Primitive Flow Table: C1 & C2 Logic Conditions

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SUMMARY

The discussion revolves around the logic conditions of a Primitive Flow Table, specifically focusing on the outputs Z based on the inputs C1 and C2. It is established that when there is an amount of C1 front, the output Z is 1, while an amount of C2 front results in Z being 0. The confusion arises from understanding stable states and transitions, particularly regarding the outputs for states S2, S3, S4, and S5. The participant seeks clarity on the interpretation of these conditions and their implications on the flow table's behavior.

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  • Understanding of digital logic design principles
  • Familiarity with state transition diagrams
  • Knowledge of flow tables and their applications
  • Basic concepts of stable states in sequential circuits
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  • Study the principles of state transition diagrams in digital circuits
  • Learn about the implementation of Primitive Flow Tables in logic design
  • Explore the concept of stable states and their significance in sequential logic
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This discussion is beneficial for students and professionals in digital logic design, particularly those working with flow tables and state machines. It is also useful for educators seeking to clarify concepts related to logic conditions and stable states.

masterchiefo
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Homework Statement


Following the amount of C1 front, the output Z be 1 .
Following an amount of C2 front, the output Z must be 0 .
Otherwise, the output remains unchanged.

Homework Equations

The Attempt at a Solution


in Attached file.

This is the answer but I really do not understand the concept of how it works and how I actually have to look at it.

For example on the row S2: S2 is the stable state(10), it can reach S4(11) and S5(00)
I don't understand why the output is 1 because my stable state C1 is 1 which make it impossible for a amount of C1 front, it would of require it to be 0 then change to 1 on either S4 or S5 which is not the case.

Do I have to read it the other way around? my transition to my stable state? in that case S5 (C1=0) so there would be a amount of C1 front to the stable state.

Also I don't understand why the row S3 and S4 is not the same output since the stable state is in the same location on both row so C1 and C2 logic condition must be the same on each row?

thanks for helping me this is all extremely confusing me and I tried really hard in 3 days to understand it :/
 

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masterchiefo said:
Following the amount of C1 front, the output Z be 1 .
Following an amount of C2 front, the output Z must be 0 .
I don't understand those statements. What does "the amount of C1 front" mean?
 

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