Probabilities and binomial theorem

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SUMMARY

The discussion focuses on calculating the probability of finding n particles in a subvolume v of an ideal gas consisting of N identical particles within a volume V. The probability P of a molecule being in the subvolume is defined as P = v/V. The solution to part (a) is derived using the binomial theorem, leading to the expression (v/V)^N = p^N. For part (b), participants are guided to calculate the average number of particles ⟨n⟩ and the variance σ² using the binomial distribution formula (p + q)ⁿ = ∑ (N! / (n!(N-n)!)) pⁿ q^(N-n).

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  • Understanding of the binomial theorem and its applications
  • Familiarity with probability concepts in statistical mechanics
  • Knowledge of ideal gas behavior and particle independence
  • Basic skills in mathematical statistics for variance calculation
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  • Study the derivation of the binomial distribution and its properties
  • Learn about statistical mechanics and the behavior of ideal gases
  • Explore advanced probability topics, including variance and expectation
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Students and professionals in physics, particularly those studying statistical mechanics, as well as anyone interested in probability theory and its applications in gas behavior.

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Homework Statement



Consider an ideal gas of N identical particles in a volume V, and a subvolume v. The chance a molecule is in inside the subvolume is P = v/V.

a) What is the chance the subvolume contains n particles?

b) Use the binomial theorem [tex](p + q)^N = \sum_{n = 0}^N p^n q^{N-n} \frac{N!}{n!(N-n)!}[/tex] for random p and q to calculate the average number of particles [tex]\langle n\rangle[/tex] and the variance [tex]\sigma^2 = \langle n^2 \rangle - \langle n \rangle^2[/tex]

Anyone who could give me a nudge in the right direction?
 
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As the gas is ideal, the particles can go inside the subvolume independently. Thus, the answer is (v/V)^N =p^N. Part (b) follows from straightforward but long calculations.
 

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