Probability of 3 Heads and 2 Tails in 5 Coin Tosses

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SUMMARY

The probability of obtaining three heads and two tails in five tosses of a fair coin is definitively calculated as 5/16. This conclusion is derived using the Bernoulli Trial formula, which is applicable for n=5 trials, with a probability p=0.5 for heads. Additionally, the total number of possible outcomes is determined to be 2^5=32, and the arrangement of outcomes is calculated using permutations, yielding a result of 10 favorable outcomes. Thus, the final probability is expressed as 10/32, simplifying to 5/16.

PREREQUISITES
  • Understanding of Bernoulli Trials
  • Knowledge of basic probability concepts
  • Familiarity with permutations and combinations
  • Basic mathematical skills for calculations
NEXT STEPS
  • Study the Bernoulli Trial formula in detail
  • Learn about permutations and combinations in probability
  • Explore the concept of independent trials in probability theory
  • Investigate other probability distributions, such as the Binomial distribution
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This discussion is beneficial for students of probability, educators teaching basic statistics, and anyone interested in understanding the mathematical principles behind coin toss probabilities.

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A fair coin is tossed five times. What is the probability of obtaining three heads and two tails?

I cannot find out the right answer by my way

Ans: 5/16

Thanks :)
 
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Since there are only two possibilities for each flip (head or tail), if you find the probability of having exactly 3 heads you've got the question answered. what distribution do you know of that

- deals with counts of a particular outcome
- assumes only two possible outcomes per trial
- assumes that successive trials are independent
 
Yes the Bernoulli Trial formula will directly yield the answer for n=5, p=0.5 and k=3.

Another way is this.
Total possible outcomes is 2^5=32
How can you Permute [arrange] 5 items, 5 at a time, with 3 the same and 2 the same ?
5 ! / [ (5-5)! 3! 2! = 10
10/32 = 5/16
 

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