Probability of spin in the +x direction

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SUMMARY

The discussion focuses on calculating the probability of a qubit's spin in the +x direction using quantum mechanics principles. The probability is derived from the state equation, specifically using the formula $$P(\sigma_x)=\langle \sigma_x|\hat{\rho}|\sigma_x \rangle$$ for a general state operator ##\hat{\rho}##. When the qubit is in a pure state represented by the ket ##|\psi \rangle##, the statistical operator becomes the projection operator ##\hat{\rho}=|\psi \rangle \langle \psi|##, leading to the application of the Born rule, expressed as $$P(\sigma_x)=|\psi(\sigma_x)|^2$$ for pure states.

PREREQUISITES
  • Understanding of qubit representation in quantum mechanics
  • Familiarity with the Born rule in quantum theory
  • Knowledge of projection operators and their application
  • Basic grasp of spinors and their role in quantum states
NEXT STEPS
  • Study the application of the Born rule in various quantum systems
  • Learn about the mathematical representation of spinors in quantum mechanics
  • Explore the concept of density matrices and their significance in mixed states
  • Investigate the implications of measurement in quantum mechanics and its effects on state collapse
USEFUL FOR

Quantum physicists, students of quantum mechanics, and researchers focusing on quantum computing and information theory will benefit from this discussion.

srallaba
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Consider a qubit.
Given a state equation, how to calculate the probability of finding spin in +x direction?
 
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If your system is prepared in the state ##\hat{\rho}## then the probability for the ##x##-component of the spin being ##\sigma_x## is
$$P(\sigma_x)=\langle \sigma_x|\hat{\rho}|\sigma_x \rangle.$$
 
How to do it if I know spinor instead of ##\hat{\rho}##?
 
If your spin is prepared in a pure state, represented by the ket ##|\psi \rangle##, then the statistical operator is the projection operator ##\hat{\rho}=|\psi \rangle \langle \psi|##, and the general formula gives you the Born rule for pure states, as it should be:

$$P(\sigma_x)=\langle \sigma_x \psi \rangle \langle \psi|\sigma_x \rangle=\psi(\sigma_x) \psi^*(\sigma_x)=|\psi(\sigma_x)|^2.$$
 

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