Probability question (Counting)

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SUMMARY

The discussion centers on calculating the number of arrangements of an 8-letter word that either starts with "BO" or ends with "BO," using the English alphabet with 26 letters and allowing for letter repetition. The calculations presented yield 26^6 for both scenarios, leading to a total of 2 * 26^6. The participant seeks clarification on whether to subtract 1 or 26^4 for the intersection case, which arises when the word both starts and ends with "BO." The correct intersection calculation involves recognizing that "BOLLLLBO" represents one specific arrangement, confirming the logic of using 26^4 for the overlap.

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jtm
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imagine a 8 letter word, how many possibilities are there to arrange letters in the alphabet (26) that start with BO(in that order) OR end with BO (in that order), if letters can be repeated?

This is my work:

1 * 1 * 26 * 26 * 26 * 26 * 26 * 26 = 26^6 +

26 * 26 * 26 * 26 * 26 * 26 * 1 * 1 = 26^6

BUT I'm not sure what the intersection is because:

do we subtract 1 or 26^4?

my logic from 26^4 is coming from BOLLLLBO <-- where L is any letter

Thank you!
 
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Your logic sounds right.
 

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