Probablity density of 1s in hydrogen atom

  • Thread starter Karrar
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  • #1
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Main Question or Discussion Point

I have two asks
first ask :
In plot of probablity density of 1s electron of hydrogen atom
when r=0 where electron exist ?
is inside nucleus?! how happen this

second ask
what is the reduis of electron ri? and what reduis of nucleos RI is ? in Hamltonain operator
i mean the defination of r for (electron) and R for( nucleus)
 

Answers and Replies

  • #2
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Here is (I think) an estimate for the probability of the electron in a 1s hydrogen orbit being inside the proton (hydrogen nucleus).

The probability of the electon being "inside the proton" according to perturbation theory is (using Dirac notation)

P = <Re(r) l Rp(r) l Re(r)>

where Re(r) is the 1s electron radial wave function and Rp(r) is the proton radial charge distribution.

Using Re(r=0) = 2/a03/2

where a0 = Bohr radius and proton radius = Rp

we get

P = [STRIKE][4/a03][4 πRp3/3][/STRIKE] = [4/a03][Rp3/3]

Note that the probability is unitless. For muonic atoms, where a muon has replaced the electron in the 1s orbit, the muon in high-Z muonic atoms spends much of its time inside the nucleus.

Bob S
 
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