Also you said,
the equation given x^2/9 + y^2/16 = 1 is distance i believe, so when you differentiate it v=2x/9 + y/8 = 0, and differentiate again would mean a=2/9+1/8=25/72. And these three equations are tangential.
This is not how you differentiate.
X^2/9+ Y^2/16=1
Differentiating
2xdx/9dt +2ydy/16dt =0
dx/dt is horizontal velocity and dy/dt is vertical velocity.
Using equation x=asin m is easier .So differentiate it.
dx/dt or Vx=acos m (dm/dt)
dm/dt is like omega
Ax= -asinm(dm/dt)^2 + a cosm(d2m/dt2)
Here -asin m(dm/dt) is x component of centripetal acceleration.
Magnitude of velocity is sqroot [(dx/dt)^2 +(dy/dt)^2]