I know why I can add [tex]2 \pi i[/tex] to [tex] log_{e} \omega [/tex](adsbygoogle = window.adsbygoogle || []).push({});

([tex] log_{e} \omega = log_{e}z + i \theta [/tex] if [tex] \omega = z(cos \theta +i sen \theta ) [/tex]) but I can't understand why I can add [tex] \frac{2 \pi i}{log_{e}b} [/tex] to [tex] log_{b} \omega [/tex].

Does anyone have the answer for me?

Thanks!

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# Problem with Logarithms solutions

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