Problems on Integers: Q1-Q3 - Solutions Needed

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Homework Help Overview

The thread discusses three problems related to integers and sequences, specifically focusing on a sequence defined by kn, the sum of irreducible fractions, and pairs of natural numbers with specific properties regarding their greatest common divisor and least common multiple.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the sequence kn and its behavior under certain conditions, questioning how to manipulate the expression to find terms within a specified range. There is also discussion about the nature of irreducible fractions and the properties of natural number pairs related to GCD and LCM.

Discussion Status

The discussion is ongoing with participants attempting to clarify the sequence's formulation and its implications. Some participants have raised questions about the interpretation of terms and the conditions under which they are evaluated, while others are exploring the implications of odd and even values of n.

Contextual Notes

There appears to be some confusion regarding the correct interpretation of the sequence notation and the conditions for the problems. Additionally, participants are navigating the forum structure and the appropriateness of posting in the "homework help" section.

steve357
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Q 1:-
Given a sequence kn=[(1+(-1)^n)+1]/5n+6..
find the no of terms of the sequence kn which will satisfy the condition kn lies between 1/100 and 39/100.

Q 2:-
Find the sum of all the irreducable fractions between 10 and 20 with a denominator of 3

Q 3:-
Find all pairs of natural no s whose greatest common divisor is 5 and L.C.M is 105

i could really not do much about these so please help! Any assistance appreciated ..
 
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Well, what did you do? And why was this not posted under "homework help"?
 
See i don't know anything about forums..like where do we even get the section "homework help"..! anyways that's not the issue here.
For the first question i tried to make the denominator 100 for which i got n in fraction now that if i put in numerator then in all probability it becomes a question of complex numbers which i don't know.For the second i am getting the answer uncountable or infinity and i don't know third
 
kn=[(1+(-1)^n)+1]/5n+6
Find the no of terms of the sequence kn which will satisfy the condition kn lies between 1/100 and 39/100.

There are none, as all the terms in the sequence are greater than 6.
 
I suppose you mean kn=[(1+(-1)n)+1]/(5n+6) .

The parentheses are important.

What you wrote literally means: k_n=\frac{(1+(-1)^n)+1}{5n}+6\,, which is how uart likely interpreted it.

There are many numbers between 1/100 and 39/100 which don't have a denominator of 100.

How many terms of the sequence are between 0.01 and 0.39 ?

The terms of the sequence with n odd look much different from the terms with n even.
 
There are many numbers between 1/100 and 39/100 which don't have a denominator of 100.

[/QUOTE]
yeah but i was trying to first find that n for which i shall get the limiting values;i mean 0.01 and 0.39. And i did not understand what you said in the second part
 
If n is odd, (-1)n = -1 .

If n is even, (-1)n = 1 .
 
yeah right i also got till there but what when n is in decimal??
 
n is a positive integer.

It's a sequence we're talking about.
 

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