Problems with the quotient property of logarithms

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To approximate log5 12 using log5 2 and log5 3, the product property of logarithms should be applied instead of the quotient property. The correct approach is to express log5 12 as log5(2 * 2 * 3), which involves adding the logarithms of the individual factors. Initially, there was confusion due to the wording of the problem, leading to an incorrect application of subtraction. Ultimately, the correct calculation is 0.4307 + 0.4307 + 0.6826, which equals approximately 1.544. Understanding the distinction between the properties of logarithms is crucial for solving such problems correctly.
alancj
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My test here asks me to: "Use log5 2 =0.4307 and log5 3=0.6826 to approximate the value of log5 12."

According to my textbook I would solve this by subtracting (using the quotient property): 0.6826-0.4307. That = 0.2519.

But that number isn't right!

log5 12=1.544 (about) Which I found by trial and error. I have to show my work on the test so I need to know how to do it the "right" way.

How would I solve this the way it was intended to be?

Thanks,
Alan
 
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You want the product property not the quotient property. log512 = log5(2 * 2 * 3).
 
0rthodontist said:
You want the product property not the quotient property. log512 = log5(2 * 2 * 3).

Yeah, but the only example that looks like my problem is the one where they are talking about the quotient property. That example has the exact same wording as the one I'm working on but just different numbers. I don't see how it would be anything else. Besides, adding 0.4307 + 0.6826 doesn't equal 1.544.

Unless I'm missing something here….

Edit:

HA! I get it now! 0.4307 + 0.4307 + 0.6826=1.544

I still hate my book.
 
Last edited:

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