1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Problems with the quotient property of logarithms

  1. Jul 28, 2006 #1
    My test here asks me to: "Use log5 2 =0.4307 and log5 3=0.6826 to approximate the value of log5 12."

    According to my textbook I would solve this by subtracting (using the quotient property): 0.6826-0.4307. That = 0.2519.

    But that number isn't right!

    log5 12=1.544 (about) Which I found by trial and error. I have to show my work on the test so I need to know how to do it the "right" way.

    How would I solve this the way it was intended to be?

  2. jcsd
  3. Jul 28, 2006 #2


    User Avatar
    Science Advisor

    You want the product property not the quotient property. log512 = log5(2 * 2 * 3).
  4. Jul 28, 2006 #3
    Yeah, but the only example that looks like my problem is the one where they are talking about the quotient property. That example has the exact same wording as the one I'm working on but just different numbers. I don't see how it would be anything else. Besides, adding 0.4307 + 0.6826 doesn't equal 1.544.

    Unless I'm missing something here….


    HA! I get it now! 0.4307 + 0.4307 + 0.6826=1.544

    I still hate my book.
    Last edited: Jul 28, 2006
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Problems with the quotient property of logarithms
  1. Quotient property (Replies: 3)

  2. Logarithmic properties (Replies: 3)

  3. Property of logarithm (Replies: 3)