Product equality and sum of squares equality puzzle

  • Thread starter K Sengupta
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  • #1
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Substitute each of the capital letters by a different digit from 0 to 9 to satisfy this set of cryptarithmetic relationships. None of the numbers can contain any leading zero.

ABCD*EF=GHJB*KE, and:

(EH)2 + (KC)2 = (KH)2
 

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  • #2
I like Serena
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abcd*ef=ghjb*ke
9807*14=6538*21

(eh)2 + (kc)2 = (kh)2
(15)2 + (20)2 = (25)2
 

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