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Sum the squares cryptarithmetically, get square

  1. Oct 26, 2008 #1
    Substitute each of the letters by a different decimal digit from 0 to 9 to satisfy this cryptarithmetic equation:

    (PQR)2 + (STUQ)2 = (SVWX)2

    Note: None of P and S can be zero.
     
  2. jcsd
  3. Oct 27, 2008 #2

    dsa

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    (125)2 + (7812)2 = (7813)2
     
  4. Nov 17, 2008 #3
    There seems to be a minor typing error.

    U = W = P = 1 contravenes the provision that each letter need to represent a different digit.
     
  5. Nov 18, 2008 #4

    dsa

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    OK, this one is better:wink:

    (480)2 + (1768)2 = (1832)2
     
  6. Nov 19, 2008 #5
    Very good, dsa.

    I am now certain that you will be able to obviate the ambiguity corresponding to V=Q=8.
     
  7. Nov 19, 2008 #6

    dsa

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    I cannot find a solution for all unique PQRSTUVWX :frown:
     
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