Sum the squares cryptarithmetically, get square

  • Thread starter K Sengupta
  • Start date
  • #1
111
0
Substitute each of the letters by a different decimal digit from 0 to 9 to satisfy this cryptarithmetic equation:

(PQR)2 + (STUQ)2 = (SVWX)2

Note: None of P and S can be zero.
 

Answers and Replies

  • #2
dsa
11
0
(125)2 + (7812)2 = (7813)2
 
  • #3
111
0
(125)2 + (7812)2 = (7813)2

There seems to be a minor typing error.

U = W = P = 1 contravenes the provision that each letter need to represent a different digit.
 
  • #4
dsa
11
0
OK, this one is better:wink:

(480)2 + (1768)2 = (1832)2
 
  • #5
111
0
OK, this one is better:wink:

(480)2 + (1768)2 = (1832)2

Very good, dsa.

I am now certain that you will be able to obviate the ambiguity corresponding to V=Q=8.
 
  • #6
dsa
11
0
Very good, dsa.

I am now certain that you will be able to obviate the ambiguity corresponding to V=Q=8.

I cannot find a solution for all unique PQRSTUVWX :frown:
 

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