- #1

moont14263

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1) If p divides |H| then P[itex]\cap[/itex]HK is a subgroup of H.

2) Is (1) when K is not normal in G.

This is my try of (1);

Let y be an element of P[itex]\cap[/itex]HK, --> |y| divides |HK|=|H|*|K|--> |y| divides |H|--> y is an element of H as the order of y does not divide the order of K. What I am saying is that the elements of p power order of the intersection come from the Sylow p-subgroups of H.

For (2);

I know that |HK|=|H|*|K| but HK may not be a subgroup of G. And in this case also the intersection may not be a subgroup of G.

Help,me please.