Proof of Sylow: Let G be a Finite Group, H and K Subgroups of G

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The discussion centers on the proof of Sylow's theorem, specifically addressing the condition that for a finite group G with subgroups H and K such that G = HK, there exists a p-Sylow subgroup P of G satisfying P = (P ∩ H)(P ∩ K). Participants express confusion regarding the clarity of this step in the proof, particularly questioning the necessity of normality in this context. The original proof can be found on Math Stack Exchange, and the problem is sourced from "Finite Group Theory" by Martin Isaacs.

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moont14263
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Let G be a finite group, H and K subgroups of G such that G=HK. Show that there exists a p-Sylow subgroup P of G such that P=(P∩H)(P∩K).

I found this proof and it is clear http://math.stackexchange.com/questions/42495/sylow-subgroups but I do not understand step 3 which is "It is clear in this situation that P=(P∩H)(P∩K)". Help.
 
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moont14263 said:
Let G be a finite group, H and K subgroups of G such that G=HK. Show that there exists a p-Sylow subgroup P of G such that P=(P∩H)(P∩K).

I found this proof and it is clear http://math.stackexchange.com/questions/42495/sylow-subgroups but I do not understand step 3 which is "It is clear in this situation that P=(P∩H)(P∩K)". Help.

+

Well, after part (3) in the stackexchange there's a further poster who also had a problem with this step, and I think it isn't THAT clear, as the other guy wrote, that P = (P/\H)(P/\K)...
The same question as that further poster asked came to my mind: is normality something we can do without?

It'd be interesting to know where did you find this problem.

DonAntonio
 
It is in Finite Group Theory I. Martin Isaacs page 18
 

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