Projectile Motion Ball Hurl Question

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yoyo16
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Homework Statement



If you can hurl a ball so that its initial speed is 30m/s, what is the widest river you can throw it across?

Homework Equations


The range equations,
t=2(vi)(sintheta)/g

d=visin2theta/g


The Attempt at a Solution



I know you have to use components so what I got what Vx=30sintheta and Vy=30costheta

I don't know what to do next or how to sub it in because there isn't a angle given . Can someone please help me. Thanks
 
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You have your formula for the range as

[tex]d = \frac{v_i sin2 \theta}{g}[/tex]

For you to throw it at the max range, you'd need to throw it such that your angle θ and hence sin2θ is maximum.

What is the maximum value that sin2θ can be?
 
rock.freak667 said:
You have your formula for the range as

[tex]d = \frac{{v_{0}}^2 sin2 \theta}{g}[/tex]

For you to throw it at the max range, you'd need to throw it such that your angle θ and hence sin2θ is maximum.

What is the maximum value that sin2θ can be?

Forgot a square!
 
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The angle must be 45 degrees to get max range right?
 
Oh ok, I got the answer. Thanks so much !