In the figure, you throw a ball toward a wall at speed 34.0 m/s and at angle θ0 = 38.0˚ above the horizontal. The wall is distance d = 20.0 m from the release point of the ball. (a) How far above the release point does the ball hit the wall? What are the (b) horizontal and (c) vertical components of its velocity as it hits the wall?
Projectile Motion Equations.
The Attempt at a Solution
So I figured out A by using the trajectory equation (solved for y).
That value became my (y-yo) in the projectile versions of the kinematics equations.
Used that to solve for the final velocity, which came out to 13.6m/s
So I used 13.6m/s as my Vy, then found the components: [13.6cos(90),13.6sin(90)]
I got the answer for part A and for part C no problem.
For part B I got zero, because the cosine of 90 is zero. Wileyplus gave me trouble. Is there some special way to express a vector component with a magnitude of zero? Did I screw up here?