Projectile Motion Kenimatics in Two Deminisions?

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Homework Help Overview

The discussion revolves around a projectile motion problem in kinematics, specifically focusing on finding the maximum height of a projectile given its initial velocity, launch angle, and gravitational acceleration.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply a formula involving the initial velocity and angle to calculate the maximum height but expresses concern about the low result. Some participants suggest that the vertical component of the initial velocity may not be sufficient to achieve a significant height.

Discussion Status

Participants are exploring different interpretations of the formula for maximum height. There is some guidance offered regarding the correct application of the sine function and squaring the vertical component of the initial velocity. However, there is no explicit consensus on the correctness of the approach or the final answer.

Contextual Notes

There is mention of potential confusion regarding the formula used and the need to clarify the components of the initial velocity in relation to gravity. The original poster also indicates uncertainty about the formula's application.

alexas
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Homework Statement


Find the maximum height of a projectile that as the following velocity and is launched at that angle.
Intial Velocity: 4.736 m/s
Angle (in degrees): 40
Gravity: -9.8 ?


I was thinking...

{((-4.736m/s)^2)(sin(40))}/{(-2)(g)} but the hieght comes out extremely low...

I have a feeling i am using a wrong formula... Any ideas?
 
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You really should be squaring the (sin40*Vo) but otherwise it won't go all that high will it, if the vertical component of Vo is about 1/3 of what gravity will knock down in 1 sec?
 
Sorry I meant to say the sin40 was also squared. Is the answer I get for thre sin^2 times v^2 divided by 2g the correct one?
 
alexas said:
Sorry I meant to say the sin40 was also squared. Is the answer I get for thre sin^2 times v^2 divided by 2g the correct one?

Looks ok to me.
 

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