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Projectile Motion Kenimatics in Two Deminisions?

  1. Mar 2, 2009 #1
    1. The problem statement, all variables and given/known data
    Find the maximum height of a projectile that as the following velocity and is launched at that angle.
    Intial Velocity: 4.736 m/s
    Angle (in degrees): 40
    Gravity: -9.8 ?

    I was thinking....

    {((-4.736m/s)^2)(sin(40))}/{(-2)(g)} but the hieght comes out extremely low...

    I have a feeling i am using a wrong formula... Any ideas?
  2. jcsd
  3. Mar 2, 2009 #2


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    Homework Helper

    Welcome to PF.

    You really should be squaring the (sin40*Vo) but otherwise it won't go all that high will it, if the vertical component of Vo is about 1/3 of what gravity will knock down in 1 sec?
  4. Mar 2, 2009 #3
    Sorry I meant to say the sin40 was also squared. Is the answer I get for thre sin^2 times v^2 divided by 2g the correct one?
  5. Mar 2, 2009 #4


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    Homework Helper

    Looks ok to me.
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