- #1

salmayoussef

- 31

- 0

## Homework Statement

Problem: A mountain climber is stranded on a ledge 30 m above the ground. Rescuers on the ground want to shoot a projectile to him with a rope attached it. If the projectile is directed upward at an initial angle of 55° from a horiontal distance of 50 m, derermine the intial speed the projectile must have in order to land on the ledge.

Given:

d

_{x}= 50 m

d

_{y}= 30 m

θ = 55°

g = -9.8 m/s

^{2}

Required:

Δt

V

_{0}

## Homework Equations

Not sure if I used the proper equation but: d = V * t - (1/2)(-9.8)(t)

^{2}

## The Attempt at a Solution

I tried finding Δt first by using t = d

_{x}/V

_{x}= 50/(cos55 * V

_{0})

After finding the time, I used it an inputed it into the equation and canceled out the V

_{0}in the numerator and denominator then I was left with one V which I had to find by rearranging the equation.

30 m = (sin55 * V

_{0})(50/(cos55 * V

_{0}) - 4.9(50/cos55 * V

_{0})

^{2}

After rearranging it, I ended up with 30.06 m/s as the initial velocity. Am I using the right equation?