A rock is thrown down off a cliff at 18 m/s at an angle of 17 below the horizontal. If the rock hits a cliff that is 16m away, how far down did the rock fall.
Vf= Vi + at
change in Y= Vit + .5at^2
The Attempt at a Solution
I tried solving for time and then plugging that back into the equations and I kept getting -3.87. Please help!