Projectile motion vector problem

[velocityay]

Homework Statement

At what compensatory angle north of east should a drone, that can only move forward at a maximum speed of 20 m/s, be launched if it is to strike a target that is 400m due east if there is a wind moving 5 m/s south?

Homework Equations

v_x=20cos\Theta
v_y=20sin\Theta
v_f²=v_i²+2ad (I think?)

The Attempt at a Solution

I'm not sure how to start trying to solve this, I drew a small diagram labeled with north south east and west and it shows the object's trajectory over the 400 m. I set up a chart of known and unknown variables
x
d=400 m
a=0 m/s²
t= ?
v_i=20cos\Theta
v_f=20cos\Theta
v_avg=20cos\Theta

y
d=?
a=9.8 m/s²
t=?
v_i=20sin\Theta
v_f=?
v_avg=?that's all I can get

 

[Jack21222]

First define your variables. What is x and what is y? Why is acceleration in the y direction 9.8 m/s^2?

 

[velocityay]

x is motion on the axis from west to east and y is motion on the axis from south to north, the acceleration in the y direction is that because the only force acting on it is the gravitational force

 

[Jack21222]

Gravity doesn't work from north to south.

EDIT: My point is, you're approaching the problem from completely the wrong angle. It's simple vector arithmetic and trigonometry. Try re-drawing the problem with that in mind, and let us know how you do.