(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A motorcyclist is going off an incline 53 degrees above the horizontal. He wants to land on a ledge 40 meters from the ledge he is launching off of, 15 meters below the edge of the ramp he is laughing off of. Δx = 40m. Δy = -15m. What is the minimum initial velocity he needs to go off the ramp at to barely make the jump?

2. Relevant equations

Vx = Vocos53

Ag = 9.8 m/s^2

Voy = Vosin53

x = Vx(t)

t = ?

y = yo + Voy(t)-1/2(a)(t)^2

3. The attempt at a solution

If this was a horizontal launch it'd be very simple, but I have no idea what to do with launching off an incline. I tried:

t = square root (2d/a) = square root ((2*15)/9.8) = 1.75 sec

x = Vx(t) therefore 40 = Vx(1.75) ; Vx = 22.86 m/s

Then; Vo = Vx/cos53 = Vo = 22.66/cos53 = 37.99 m/s. The book says this is wrong and I have no idea what to do.

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# Homework Help: Projectile Motion with different starting and ending heights

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