1. Sep 16, 2011

### csharsha

1. The problem statement, all variables and given/known data

When a rifle is fired horizontally at a target P on a screen at a range of 25 m, the bullet strikes the screen at a point 5.0 mm below P. The screen is now moved to a distance of 50 m and the rifle again fired horizontally at P in its new position.

Assuming that air resistance may be neglected, what is the new distance below P at which the screen would now be struck?

2. Relevant equations

Horizontal Range = (u^2sin(2w))/g

All the rest simple equations.

3. The attempt at a solution

I seriously cannot do this question, I would put my attempt if I could.

Also, if someone could help me out with this. In a velocity selector, is a particle travelling in y-direction having acceleration? And is the x-component of the velocity constant?

Thanks!!

2. Sep 16, 2011

### Staff: Mentor

If you drop the bullet out of your hand, how long does it take to fall 5mm?

What is the ratio of the time it takes the rifle bullet to travel 25m versus 50m?