1. The problem statement, all variables and given/known data When a rifle is fired horizontally at a target P on a screen at a range of 25 m, the bullet strikes the screen at a point 5.0 mm below P. The screen is now moved to a distance of 50 m and the rifle again fired horizontally at P in its new position. Assuming that air resistance may be neglected, what is the new distance below P at which the screen would now be struck? 2. Relevant equations Horizontal Range = (u^2sin(2w))/g All the rest simple equations. 3. The attempt at a solution I seriously cannot do this question, I would put my attempt if I could. Also, if someone could help me out with this. In a velocity selector, is a particle travelling in y-direction having acceleration? And is the x-component of the velocity constant? Thanks!!