Proof: Nilpotent Matrix A & Real Matrices AB-BA=I

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A nilpotent matrix A satisfies the condition a^k = 0 for some k > 0, which implies that the matrix I + A is always invertible. Furthermore, the equation AB - BA = I has no solutions in n x n matrices with real entries, as demonstrated through the application of the matrix trace function. The discussion also suggests exploring the power series representation of (1+x)^{-1} to gain further insights into the problem.

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1. A square matrix A is called nilpotent if a^k = 0 for some k > 0. Prove that if A is nilpotent, then I + A is invertible.

2. Show that the equation AB - BA = I has no solutions in n x n matrices with real entries.
 
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Regarding 2, try to use the matrix trace function.
 
1) Forget matrices. You want to find

(1+x)^{-1}

well, what is that as a power series?
 

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