Proof of Electromagnetic Identity: Puzzling Last Expression

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
larginal
Messages
3
Reaction score
2
Homework Statement
two identities in electromagentics
Relevant Equations
curl of gradientV = 0
question.jpg

I tried to understand proof of this identity from electromagnetics. but I was puzzled at the last expression.
why is that line integral of dV = 0 ?
In fact, I'm wondering if this expression makes sense.
 
Last edited by a moderator:
Physics news on Phys.org
If you had a curve integral along a curve ##\Gamma## with endpoints ##p## and ##q##, what would the integral
$$
\int_\Gamma dV
$$
be? Note that
$$
\int_\Gamma dV = \int_0^1 \frac{dV}{dt} dt
$$
if we assume that ##t## is a curve parameter in the interval [0,1] parametrising the curve such that ##p = \Gamma(0)## and ##q = \Gamma(1)##.
 
Reply
  • Like
Likes   Reactions: JD_PM, docnet and etotheipi
I got it. Thanks! is it your intention that you didn't complete the explanation to make me think?
 
Reply
  • Like
Likes   Reactions: berkeman and etotheipi