Proof of relationship between Hamiltonian and Energy

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SUMMARY

The discussion focuses on proving the relationship between the Hamiltonian and energy in quantum mechanics, specifically the equation $$\left(\frac{\partial H}{\partial\lambda}\right)_{nn} = \frac{\partial E_{nn}}{\partial\lambda}$$. Participants explore the implications of this relationship for calculating the average force exerted by a particle in an infinitely deep potential well, leading to the expression $$\langle F_\textrm{right}\rangle_n = \frac{\partial E_n}{\partial a}$$. The calculated force is $$\frac{\partial E_n}{\partial a} = -\frac{n^2\pi^2\hbar^2}{m a^3}$$, which aligns with classical mechanics principles.

PREREQUISITES
  • Understanding of Hamiltonian mechanics
  • Familiarity with quantum mechanics concepts, particularly wavefunctions
  • Knowledge of potential wells in quantum systems
  • Proficiency in calculus, specifically differentiation
NEXT STEPS
  • Study the derivation of the Hamiltonian operator in quantum mechanics
  • Learn about the implications of the Schrödinger equation in potential wells
  • Investigate the relationship between quantum forces and classical mechanics
  • Explore advanced topics in perturbation theory and its applications
USEFUL FOR

Students and researchers in physics, particularly those focusing on quantum mechanics and theoretical physics, will benefit from this discussion. It is also valuable for educators teaching advanced quantum mechanics concepts.

andre220
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Homework Statement



Prove the relationship
$$\left(\frac{\partial H}{\partial\lambda}\right)_{nn} = \frac{\partial E_{nn}}{\partial\lambda},$$
where ##\lambda## is a parameter in the Hamiltonian. Using this relationship, show that the average force exerted by a particle in an infinitely deep potential well ##(0\le x\le a)##, on the right "wall" can be written as $$\langle F_\textrm{right}\rangle_n = \frac{\partial E_n}{\partial a},$$ where ##n## is the energy level. Calculate the force and compare it with the classical expression.

Homework Equations



For the first part: ##\hat{H}_\lambda|\psi_\lambda\rangle = E_\lambda|\psi_\lambda\rangle##

##\langle \psi_\lambda|\psi_\lambda\rangle = 1##
##\frac{d}{d\lambda}\langle \psi_\lambda|\psi_\lambda\rangle = 0##

For the well: ##E_n = \frac{n^2\pi^2\hbar^2}{2ma^2}##

The Attempt at a Solution


Okay so here is what I am thinking for the first part:

$$\begin{eqnarray}
\frac{d E_\lambda}{d\lambda} & = & \frac{d}{d\lambda}\langle\psi_\lambda|\hat{H}_\lambda|\psi_\lambda\rangle \\
& = & \langle \frac{d\psi_\lambda}{d\lambda}|\hat{H}_\lambda|\psi_\lambda\rangle + \langle\psi_\lambda |\hat{H}_\lambda|\frac{d\psi_\lambda}{d\lambda}\rangle + \langle\psi_\lambda|\frac{d\hat{H}_\lambda}{d\lambda}|\psi_\lambda\rangle \\
& = & E_\lambda \langle\frac{d\psi_\lambda}{d\lambda}|\psi_\lambda\rangle + E_\lambda\langle\psi_\lambda|\frac{d\psi_\lambda}{d\lambda}\rangle + \langle\psi_\lambda|\frac{d\hat{H}_\lambda}{d\lambda}|\psi_\lambda\rangle\\
& = & \langle \psi_\lambda |\frac{d\hat{H}_\lambda}{d\lambda}|\psi_\lambda\rangle
\end{eqnarray}$$

I am not sure if this is the correct direction to go but I figured it was worth a try. Any help or comments are appreciated.
 
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Yes, your approach looks reasonable and will lead you correct. One small note on notation: I would write
$$
\frac{d\left| \psi\right>}{d\lambda}
$$
instead of
$$
\left|\frac{d\psi}{d\lambda}\right>.
$$
 
Okay thank you for your reply. Now for the second part I have
$$\frac{\partial E_n}{\partial a} = -\frac{n^2\pi^2\hbar^2}{m a^3}$$. Now I need the average force on the right "wall", and my thought to get that is using ##-\vec{\nabla} U##, then
$$\begin{eqnarray}
\langle F_\textrm{right}\rangle &= & - \int \psi_\lambda^*\vec{\nabla}\psi_\lambda\,dq\\
& = & -\int\psi_\lambda^* \frac{dU}{dx}\psi_\lambda\, dx
\end{eqnarray}$$
So my thought here is to just use the wavefunction for the infinitely deep potential well and more less plug-and-chug, but I could see some problems with that. However, I suppose in some sense this method is using the knowledge from part a.
 

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