Proof: Quadratic Nth Term of Sequence Indicates Arithmetic Progression

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Homework Help Overview

The discussion revolves around the claim that if the nth term of a sequence is a quadratic expression in n, then the sequence is an arithmetic progression (A.P.). Participants are examining the validity of this statement through various examples and reasoning.

Discussion Character

  • Conceptual clarification, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants are testing the claim by substituting values into quadratic expressions and analyzing the differences between terms. Some question the correctness of the book's statement, while others provide examples of sequences derived from quadratic expressions and discuss their properties.

Discussion Status

The discussion is active, with participants exploring different interpretations of the original claim. Some have provided examples that challenge the assertion, while others suggest that the differences between terms in a quadratic sequence may form an arithmetic progression instead.

Contextual Notes

There is an ongoing debate about the conditions under which a quadratic sequence can be considered an arithmetic progression, particularly focusing on the nature of the differences between terms and the implications of the sum of a sequence being quadratic.

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Homework Statement


Is this statement correct?

If the nth term of a sequence is a quadratic expression in n, then the sequence is an A.P.


Homework Equations





The Attempt at a Solution



Take arbitrary t(n)=n^2-2n-2
I substituted 1,2,3 in the above expression and noted the c.d.
It is not constant.
But the book says that this statement is correct.
Any ideas?
 
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The book's statement doesn't seem correct to me. The simplest sequence that fits the description is an = {n2} = {1, 4, 9, 16, ..., n2, ...} This is definitely not an arithmetic sequence for the reason you stated - the difference between pairs of successive terms is not constant.
 
Thanks!
 
If the terms of a sequence are from a quadratic formula, then the difference between the nth and (n-1)st terms form an arithmetic progression.

For example if the sequence is 1,4,9,16,25,...

then the differences are

4-1, 9-4, 16-9, 25-16,...
3,5,7,9,...

That might be what they meant to refer to
 
It is true only in case on n^2 (may be in some other cases too).
But if you take an expression like n^2 +2n-1, then Tn- T(n-1)=2n is not independent of n i.e. it is not a constant.
 
The sequence whose nth term is 2n is an arithmetic progression
 
You did not get me. In my expression, 2n is the difference between two consecutive terms of the sequence. It is not the nth term.
If you take nth term of the sequence as 2n, it violates the question as it is not a quadratic expression.
 
What I said is that the sequence whose nth term is the difference between consecutive terms of the quadratic sequence is an arithmetic progression. So for your example, the nth term of the sequence I'm describing is T(n)-T(n-1), and this new sequence is an arithmetic progression
 
If the sum (form i= 1 to n) of a sequence of numbers is a quadratic function of n, then the sequence is arthmetic.
 
  • #10
Can you give an example?
 
  • #11
HallsofIvy said:
If the sum (form i= 1 to n) of a sequence of numbers is a quadratic function of n, then the sequence is arthmetic.

Abdul Quadeer said:
Can you give an example?
The sum of the first n integers.
[tex]\sum_{k= 1}^n k = \frac{n(n + 1)}{2}[/tex]
 
  • #12
Thanks!
 

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