- #1

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log2(i) = m/n

2^(m/n) = i

2^m = i^n

2^0 = i^4 = 1

so that means that log2(i) is rational because there are integers n and m so that log2(i) = m/n , they are m=0 and n=4.

But what I do get about this proof is that it seems to imply that log2(i) = 0/4 = 0 while google says it is 2.26618007 i. So what is going on here? Is my proof wrong?