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Proof that time <0 for tachyons > c

  1. Sep 16, 2016 #1
    1. The problem statement, all variables and given/known data

    Derive the result DeltaT <0 for U> (sqrt(1-v^2/c^2)+1)/v/c)c

    2. Relevant equations

    DeltaT = u/l + (u-v/1-uv/c^2)1/l

    Where:
    DeltaT is the time for the tachyon to go and come back.
    u is the velocity of the tachyon
    l is the distance that the tachyon goes
    v is the velocity of the receiving end moving away from the tachyon
    c is the speed of light
    3. The attempt at a solution

    I tried to substitute values for u(2c),l(100m) and v(0.5c) but it gives me DeltaT = something/0 and I'm trying to get time less than zero, not infinite time.

    I'm not sure that I need to put values in the equations to proof that DeltaT <0 for U> (sqrt(1-v^2/c^2)+1)/v/c)c .
     
  2. jcsd
  3. Sep 21, 2016 #2
    If you get time less than zero, doesn't that mean you have turned the tachyon into antimatter? Or does matter/antimatter not apply to tachyons?
     
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