Proof that time <0 for tachyons > c

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SUMMARY

The discussion centers on the derivation of the result DeltaT < 0 for tachyons, specifically using the equation DeltaT = u/l + (u-v)/(1-uv/c^2) * 1/l. The user attempted to substitute values for the tachyon's velocity (u = 2c), distance (l = 100m), and the velocity of the receiving end (v = 0.5c), but encountered a division by zero, leading to an infinite time result. The user questions whether achieving a negative time implies a transformation of tachyons into antimatter, highlighting the complexities of tachyon behavior in relation to matter and antimatter.

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  • Familiarity with the speed of light (c) and its implications in physics
  • Knowledge of algebraic manipulation of equations in physics
  • Basic understanding of matter and antimatter interactions
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  • Study the mathematical foundations of special relativity, focusing on time dilation
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1. Homework Statement

Derive the result DeltaT <0 for U> (sqrt(1-v^2/c^2)+1)/v/c)c

Homework Equations



DeltaT = u/l + (u-v/1-uv/c^2)1/l

Where:
DeltaT is the time for the tachyon to go and come back.
u is the velocity of the tachyon
l is the distance that the tachyon goes
v is the velocity of the receiving end moving away from the tachyon
c is the speed of light

The Attempt at a Solution


[/B]
I tried to substitute values for u(2c),l(100m) and v(0.5c) but it gives me DeltaT = something/0 and I'm trying to get time less than zero, not infinite time.

I'm not sure that I need to put values in the equations to proof that DeltaT <0 for U> (sqrt(1-v^2/c^2)+1)/v/c)c .
 
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If you get time less than zero, doesn't that mean you have turned the tachyon into antimatter? Or does matter/antimatter not apply to tachyons?
 

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