Proof that time <0 for tachyons > c

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1. Homework Statement

Derive the result DeltaT <0 for U> (sqrt(1-v^2/c^2)+1)/v/c)c

Homework Equations



DeltaT = u/l + (u-v/1-uv/c^2)1/l

Where:
DeltaT is the time for the tachyon to go and come back.
u is the velocity of the tachyon
l is the distance that the tachyon goes
v is the velocity of the receiving end moving away from the tachyon
c is the speed of light

The Attempt at a Solution


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I tried to substitute values for u(2c),l(100m) and v(0.5c) but it gives me DeltaT = something/0 and I'm trying to get time less than zero, not infinite time.

I'm not sure that I need to put values in the equations to proof that DeltaT <0 for U> (sqrt(1-v^2/c^2)+1)/v/c)c .
 
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If you get time less than zero, doesn't that mean you have turned the tachyon into antimatter? Or does matter/antimatter not apply to tachyons?